document.write( "Question 70244: Bob invested $20,000, part at 14% and part at 13%. If the total interest at the end of the year is $2,720, how much did he invest at 14%?\r
\n" );
document.write( "\n" );
document.write( "thanks \n" );
document.write( "
Algebra.Com's Answer #50105 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! .14X+.13(20000-X)=2720 \n" ); document.write( ".14X+2600-.13X=2720 \n" ); document.write( ".01X=2720-2600 \n" ); document.write( ".01X=120 \n" ); document.write( "X=120/.01 \n" ); document.write( "X=12000 AMOUNT INVESTED @ 14% \n" ); document.write( " |