document.write( "Question 70244: Bob invested $20,000, part at 14% and part at 13%. If the total interest at the end of the year is $2,720, how much did he invest at 14%?\r
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Algebra.Com's Answer #50105 by checkley75(3666)\"\" \"About 
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.14X+.13(20000-X)=2720
\n" ); document.write( ".14X+2600-.13X=2720
\n" ); document.write( ".01X=2720-2600
\n" ); document.write( ".01X=120
\n" ); document.write( "X=120/.01
\n" ); document.write( "X=12000 AMOUNT INVESTED @ 14%
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