document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=830956>Question 830956</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the lenght of a rectangle is 2 m more than three times its width. If the area is 20 m2 find the diimensions of the rectangle to the nearest hundreth of a meter </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501021 by </B><A HREF=/tutors/aboutme.mpl?userid=Elomeht><B>Elomeht(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Elomeht><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501021\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.  The dimensions of the rectangle are x and 3x + 2<BR>\n" );
document.write( "2.  Since the area is 20, we have x(3x + 2) = 20<BR>\n" );
document.write( "3.  This becomes (after rearranging) 3x^2 + 2x - 20 = 0<BR>\n" );
document.write( "4.  Applying the quadratic solution (ignoring negative possibilities), x = (-2 + Square_Root(4 + 240))/6 = 2.27<BR>\n" );
document.write( "5.  That was the width.  The length is 2 + 3 times 2.27 = 2 + 6.81 = 8.81<BR>\n" );
document.write( "6.  Check:  2.27 times 8.81 = 19.999, which proves that the answers are correct </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );