the 3rd and 6th term of a geometric progression are 48 and 14 2/9 respectively.
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document.write( "a1, a2, a3=48, a4, a5, a6=
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document.write( "You need this formula for the nth term:\r\n" );
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document.write( "an = a1·r(n-1)\r\n" );
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document.write( "[Some books and teachers use \"t\" for \"term\" instead of \"a\".\r\n" );
document.write( "I'll use \"a\".]\r\n" );
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document.write( "the 3rd and 6th term of a geometric progression are 48 and 14 2/9 respectively.
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document.write( "a3 = a1·r(3-1)\r\n" );
document.write( "48 = a1·r2\r\n" );
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document.write( "a6 = a1·r(6-1)\r\n" );
document.write( "
= a1·r5\r\n" );
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document.write( "Change
to an improper fraction
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document.write( "
= a1·r5\r\n" );
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document.write( "Clear of fractions by multipolying both sides by 9\r\n" );
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document.write( "128 = 9a1·r5\r\n" );
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document.write( "So you have this system of equations:\r\n" );
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document.write( " 48 = a1·r2\r\n" );
document.write( "128 = 9a1·r5\r\n" );
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document.write( "Solve the first for a1\r\n" );
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document.write( "

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document.write( "

\r\n" );
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document.write( "
= a1\r\n" );
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document.write( "Substitute in\r\n" );
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document.write( "128 = 9
·r5\r\n" );
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document.write( "128 =
\r\n" );
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document.write( "Divide on the right by subtracting exponents:\r\n" );
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document.write( "128 = 432r³\r\n" );
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document.write( "Divide both sides by 432\r\n" );
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=
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document.write( "Reduce the fraction on the left and cancel on the right:\r\n" );
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=
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document.write( "
= r³\r\n" );
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document.write( "The cube root of 8 is 2 and the cube root of 27 is 3, so\r\n" );
document.write( "taking cube roots of both sides:\r\n" );
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document.write( "
= r\r\n" );
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document.write( "Substitute for r in\r\n" );
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document.write( "
= a1\r\n" );
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document.write( "
= a1\r\n" );
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document.write( "
= a1 \r\n" );
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document.write( "To divide by a fraction, invert it and multiply\r\n" );
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document.write( "
= a1\r\n" );
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document.write( "4 goes into 48 12 times:\r\n" );
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document.write( " 12\r\n" );
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= a1\r\n" );
document.write( " 1\r\n" );
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document.write( "108 = a1\r\n" );
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document.write( "Write down the 1st 4 terms of the geometric progression.
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document.write( "1st term =
,\r\n" );
document.write( "2nd term = 

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document.write( "3rd term = 

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document.write( "4th term = 

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document.write( "the 3rd term checks, but to check the whole thing,\r\n" );
document.write( "lets see if the 6th term is
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document.write( "5th term = 



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document.write( "6th term = 



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document.write( "So it checks.\r\n" );
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document.write( "Edwin
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