document.write( "Question 830722: A new cruise ship line has just launched 3 new ahips; the Pacific Paradise, the Caribbean Paradise, and the Mediterranean Paradise. The Caribbean Paradise has 13 more deluxe staterooms than the Pacific Paradise. The Mesitterean Paradise has 40 fewer deluxe staterooms than four times the number of deluxe staterooms on the Pacific Paradise. Find the number of deluxe staterooms for each of the ships if the total number of deluxe staterooms for the three ships is 615 \n" ); document.write( "
Algebra.Com's Answer #500991 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! Let P be the Pacific \n" ); document.write( "Let C be the Caribbean \n" ); document.write( "Let M be the Mediterranean \n" ); document.write( ". \n" ); document.write( "Here is the information given in the problem: \n" ); document.write( "C = P + 13 \n" ); document.write( "M = 4P - 40 \n" ); document.write( "C + P + M = 615 \n" ); document.write( ". \n" ); document.write( "Let's rewrite the problem substituting the values given in the question. \n" ); document.write( "C + P + M = 615 \n" ); document.write( "(P+13) + P + (4P-40) = 615 \n" ); document.write( "Add the Ps \n" ); document.write( "6P + 13 - 40 = 615 \n" ); document.write( "Do the addition and subtraction \n" ); document.write( "6P - 27 = 615 \n" ); document.write( "Add 27 to each side \n" ); document.write( "6P = 642 \n" ); document.write( "Divide each side by 6 \n" ); document.write( "P = 107 \n" ); document.write( ". \n" ); document.write( "If P is 107, then C is 107+13, or 120 \n" ); document.write( "If P is 107, then M is (4*107)-40, or 428-40, or 388 \n" ); document.write( "Add them together to make certain the problem is correct. \n" ); document.write( "107 + 120 + 388 does indeed equal 615. \n" ); document.write( "Success! \n" ); document.write( ". \n" ); document.write( "And now I'm ready to sail on the Princess Ruby! \n" ); document.write( " |