document.write( "Question 830813: Briefly describe how the graph can be obtained from the graph of a basic logarithmic function. Then graph the function. Give the domain and the vertical asymptote of each function.\r
\n" ); document.write( "\n" ); document.write( "f(x) = 5 - 2 log (x+1) \n" ); document.write( "
Algebra.Com's Answer #500980 by lwsshak3(11628)\"\" \"About 
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Briefly describe how the graph can be obtained from the graph of a basic logarithmic function. Then graph the function. Give the domain and the vertical asymptote of each function.
\n" ); document.write( "f(x) = 5 - 2 log (x+1)
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\n" ); document.write( "Basic log(x) function:
\n" ); document.write( "vertical asymptote: x=0 or y-axis
\n" ); document.write( "domain:(0,∞)
\n" ); document.write( "point on curve: (1,0)
\n" ); document.write( "..
\n" ); document.write( "-2log(x+1)
\n" ); document.write( "basic curve moves one unit to the left
\n" ); document.write( "curve stetches 2 units
\n" ); document.write( "negative sign results in curve flipping around the x-axis to its mirror image
\n" ); document.write( "vertical asymptote: x=-1
\n" ); document.write( "domain:(-1,∞)
\n" ); document.write( "point on curve: (0,0)
\n" ); document.write( "..
\n" ); document.write( "5-2log(x+1)
\n" ); document.write( "entire curve raised vertically 5 units
\n" ); document.write( "vertical asymptote: x=-1
\n" ); document.write( "domain:(-1,∞)
\n" ); document.write( "point on curve: (0,5)
\n" ); document.write( "..
\n" ); document.write( "Sorry, I don't have the means to draw the curve for you.\r
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