document.write( "Question 830855: If angle X is the angle of elevation from a point on the ground to the top of a tree, and if sinX=40/41 and the tree is 20 feet high, then how far from the base of the tree is the point on the ground? \n" ); document.write( "
Algebra.Com's Answer #500966 by stanbon(75887)\"\" \"About 
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If angle X is the angle of elevation from a point on the ground to the top of a tree, and if sinX=40/41 and the tree is 20 feet high, then how far from the base of the tree is the point on the ground?
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\n" ); document.write( "Draw the picture:
\n" ); document.write( "You have a right triangle.
\n" ); document.write( "Base angle (X) has sin(X)= 40/41.
\n" ); document.write( "Side opposite is 20 ft
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\n" ); document.write( "Equation:
\n" ); document.write( "y/r = 40/41
\n" ); document.write( "20/r = 40/41
\n" ); document.write( "r = 20*41/40
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\n" ); document.write( "r = 20.5
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\n" ); document.write( "Ans: base = sqrt[20.5^2-20^2] = 4.5 ft
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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