document.write( "Question 830855: If angle X is the angle of elevation from a point on the ground to the top of a tree, and if sinX=40/41 and the tree is 20 feet high, then how far from the base of the tree is the point on the ground? \n" ); document.write( "
| Algebra.Com's Answer #500966 by stanbon(75887)      You can put this solution on YOUR website! If angle X is the angle of elevation from a point on the ground to the top of a tree, and if sinX=40/41 and the tree is 20 feet high, then how far from the base of the tree is the point on the ground? \n" ); document.write( "--------- \n" ); document.write( "Draw the picture: \n" ); document.write( "You have a right triangle. \n" ); document.write( "Base angle (X) has sin(X)= 40/41. \n" ); document.write( "Side opposite is 20 ft \n" ); document.write( "--- \n" ); document.write( "Equation: \n" ); document.write( "y/r = 40/41 \n" ); document.write( "20/r = 40/41 \n" ); document.write( "r = 20*41/40 \n" ); document.write( "------ \n" ); document.write( "r = 20.5 \n" ); document.write( "----- \n" ); document.write( "Ans: base = sqrt[20.5^2-20^2] = 4.5 ft \n" ); document.write( "------------------------------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "===================== \n" ); document.write( " |