document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=830869>Question 830869</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Sum of Two numbers is 44 and their quotient is 3/8. Find the numbers  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #500963 by </B><A HREF=/tutors/aboutme.mpl?userid=Bastian21><B>Bastian21(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Bastian21><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=500963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 1st N0# = N <BR>\n" );
document.write( "And 2nd NO3 = 44-N <BR>\n" );
document.write( "Therefore\r<BR>\n" );
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document.write( "N/ (44-N) = 3/8 <BR>\n" );
document.write( "Cross Multiply we get\r<BR>\n" );
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document.write( "8N= 132-3N <BR>\n" );
document.write( "8N + 3N = 132 <BR>\n" );
document.write( "11N =132<BR>\n" );
document.write( "N=132/11 =12 is the first Number<BR>\n" );
document.write( "Hence,\r<BR>\n" );
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document.write( "44-12 = 32 is the 2nd Number  </SPAN>\n" );
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