document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=830868>Question 830868</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is greater than its width by 4 cm.  if the perimeter of the rectangle is 80 ' FIND THE SIDES OF  THE RECTANGLE.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #500962 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=500962\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter is a fence around.  It requires 2 lengths of fence + 2 widths of fence. (P = 2L + 2W)<BR>\n" );
document.write( "You're given the following information:<BR>\n" );
document.write( "P = 80<BR>\n" );
document.write( "L = W + 4<BR>\n" );
document.write( "Substitute the value for L in the original equation:<BR>\n" );
document.write( "P (80) = 2(W+4) + 2W<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "80 = 2W + 8 + 2W<BR>\n" );
document.write( "Add the Ws<BR>\n" );
document.write( "80 = 4W + 8<BR>\n" );
document.write( "Subtract 8 from each side<BR>\n" );
document.write( "72 = 4W<BR>\n" );
document.write( "Divide each side by 4<BR>\n" );
document.write( "18 = W<BR>\n" );
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document.write( "Since you know the width is 18, you can find the length by adding 4.  18+4=22<BR>\n" );
document.write( "Let's make certain by putting in the values:<BR>\n" );
document.write( "2(22) + 2(18) = 80<BR>\n" );
document.write( "44 + 36 does indeed equal 80. </SPAN>\n" );
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