document.write( "Question 830863: the length of a rectangle is three times its width, find the width if its perimeter is 100ft \n" ); document.write( "

Algebra.Com's Answer #500948 by JulietG(1812) $\"\"$ $\"About$

You can put this solution on YOUR website!
We know that the perimeter (like a fence) is 2 pieces of the length and 2 pieces of the width. P = 2L + 2W
\n" ); document.write( "The problem tells us that L = 3W (\"length is three times its width\")
\n" ); document.write( "The perimeter is given as 100'.
\n" ); document.write( ".
\n" ); document.write( "Now we just have to plug in the values.
\n" ); document.write( "100 (P) = 2L + 2W
\n" ); document.write( "Substitute the value for L
\n" ); document.write( "100 = 2(3W) + 2W
\n" ); document.write( "Multiply
\n" ); document.write( "100 = 6W + 2W
\n" ); document.write( "Add
\n" ); document.write( "100 = 8W
\n" ); document.write( "Divide each side by 8
\n" ); document.write( "12.5 = W
\n" ); document.write( ".
\n" ); document.write( "Now that we know W, we can find L (\"length is three times its width\")
\n" ); document.write( "L = 3* W (12.5)
\n" ); document.write( "L = 37.5
\n" ); document.write( ".
\n" ); document.write( "Let's check to be certain.
\n" ); document.write( "P = 2(37.5) + 2(12.5)
\n" ); document.write( "P = 75 + 25
\n" ); document.write( "100 = 75 + 25
\n" ); document.write( ".
\n" ); document.write( "Success! \n" ); document.write( "

\n" );