document.write( "Question 70245: One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number. \n" ); document.write( "

Algebra.Com's Answer #50093 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let L=larger number and S=smaller. The larger number (L) can be represented as 12 more than the smaller (or equal to 12+smaller). So
\n" ); document.write( " $\"L=12%2BS\"$
\n" ); document.write( "And we're given the fact that the sum of the smaller and twice the larger is 39 which can be represented as
\n" ); document.write( " $\"S%2B2L=39\"$
\n" ); document.write( "Now the L from the first equation can be substituted into the 2nd equation
\n" ); document.write( " $\"S%2B2%2Ahighlight%2812%2BS%29=39\"$ Now solve for S
\n" ); document.write( " $\"S%2B24%2B2S=39\"$
\n" ); document.write( " $\"3S%2B24=39\"$
\n" ); document.write( " $\"3S=15\"$
\n" ); document.write( " $\"S=5\"$
\n" ); document.write( "Now plug this back into the first equation
\n" ); document.write( " $\"L=12%2Bhighlight%285%29\"$
\n" ); document.write( " $\"L=17\"$
\n" ); document.write( "So the smaller number is 5 and the larger is 17. \n" ); document.write( "

\n" );