document.write( "Question 70248: Solve the system by addition.
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	–5x + 2y = 10
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document.write( "	  x – 3y = 11 

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Algebra.Com's Answer #50091 by jim_thompson5910(35256)\"\" \"About 
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	–5x + 2y = 10
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document.write( "	  x – 3y = 11 

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document.write( "Multiply the bottom equation by 5, this gives you 5x so it cancels with -5x\r
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	–5x + 2y = 10
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document.write( "	 5(x – 3y = 11) 

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document.write( "it then becomes\r
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	–5x + 2y = 10
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document.write( "	 5x –15y = 55 

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document.write( "Now individually add the terms 5x and -5x to get 0x. Then add 2y and -15y to get -13y, and finally 10 and 55 to get 65
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	0x - 13y = 65 

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document.write( "Now you can solve for y
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  \"+cross%28-13%2F-13%29y+=+65%2F-13\" 
Divide both sides by -13
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document.write( "So y=-5. Now solve for x by plugging in y.
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document.write( "\"-5x%2B2%28-5%29=10\"
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document.write( "\"-5x%2Bcross%28-10%2B10%29=10%2B10\"Add 10 to both sides
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document.write( "\"-5x=20\"Simplify
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document.write( "\"cross%28-5%2F-5%29x=%2820%2F-5%29\"Divide both sides by -5
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document.write( "\"x=-4\"
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document.write( "So x=-4 and y=-5 \n" );
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