document.write( "Question 70148This question is from textbook College Algebra Essentials
\n" ); document.write( ": (x - 4)2/3 power = 16 \n" ); document.write( "
Algebra.Com's Answer #50088 by bucky(2189)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"%28x-4%29%5E%282%2F3%29+=+16\"
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\n" ); document.write( "Cube both sides. In the case of the left side that means multiplying it by itself so that
\n" ); document.write( "the multiplications are:
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\n" ); document.write( "\"%28x-4%29%5E%282%2F3%29%2A%28x-4%29%5E%282%2F3%29%2A%28x-4%29%5E%282%2F3%29\"
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\n" ); document.write( "But when you multiply a base term [in this case the base is (x-4)] that has an exponent by
\n" ); document.write( "the same base term with other exponents, the product is the same base term, but the new
\n" ); document.write( "exponent is the sum of the exponents. For example \"x%5Ea+%2Ax%5Eb%2Ax%5Ec=+x%5E%28a%2Bb%2Bc%29\"
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\n" ); document.write( "In the case of taking the cube of\r
\n" ); document.write( "\n" ); document.write( "\"%28x-4%29%5E%282%2F3%29\"\r
\n" ); document.write( "\n" ); document.write( "the product will be
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\n" ); document.write( "That is it cube of the left side of the original problem. And since we cubed the left
\n" ); document.write( "side, we must also cube the right side. 16 cubed is \"16%2A16%2A16\".
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\n" ); document.write( "We have now converted the original problem to:
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\n" ); document.write( "\"%28x-4%29%5E2+=+16%2A16%2A16\"
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\n" ); document.write( "Now take the square root of both sides. The left side becomes just \"x-4\". The first
\n" ); document.write( "two terms on the right side are \"16%2A16\" and this can be written as \"16%5E2\".
\n" ); document.write( "This gets multiplied by the remaining 16 to become:
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\n" ); document.write( "\"%2816%5E2%29%2A16\"
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\n" ); document.write( "If you now take the square root of this product you get:
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\n" ); document.write( "\"sqrt%28%2816%5E2%29%2A16%29+=+sqrt%2816%5E2%29%2Asqrt%2816%29+=+16%2A4+=+64\"
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\n" ); document.write( "Substituting this in to expression results in:
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\n" ); document.write( "\"x-4+=+64\"
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\n" ); document.write( "Finally, add 4 to both sides to get:
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\n" ); document.write( "\"x+=+68\"
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\n" ); document.write( "I hope you are able to follow all the detail. You can check the answer by substituting
\n" ); document.write( "this value for x into the original problem so that \"x-4\" becomes 64. Then find the
\n" ); document.write( "cube root of 64 and square it. Or you may opt to square 64 and take the cube root of
\n" ); document.write( "that number. In both cases you should get 16, the same number as on the right side of
\n" ); document.write( "the original problem statement.
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