document.write( "Question 830762: $\"+-%283%29%2F%282%2Asqrt%28x%5E5%29%29+=+-%283%2Asqrt%28x%29%29%2F%282x%5E3%29+\"$ is true when x>0\r
\n" ); document.write( "\n" ); document.write( "i know that $\"+sqrt%28x%29=x%5E%281%2F2%29+\"$ and that when moving a variable from the numerator to the denominator we change the sign of the exponent,, yet i still can't figure how did the left part become the right part of the equation?
\n" ); document.write( "could you show me a step by step operation\r
\n" ); document.write( "\n" ); document.write( "and i've checked it at wolframalpha[dot]com [-(3)\(2*sqrt(x^5))=-(3*sqrt(x))/(2x^3)] and it says it's true so there's no error in the equation \n" ); document.write( "

Algebra.Com's Answer #500842 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Let's start with the left side and see\r\n" );
document.write( "if we can get it in the form of the\r\n" );
document.write( "right side:\r\n" );
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document.write( "Let's rationalize the denominator. We can't take \r\n" );
document.write( "the square root of an odd power of x without \r\n" );
document.write( "leaving a square root, as we could if it\r\n" );
document.write( "were an even power of x. So let's get an even\r\n" );
document.write( "power of x under the square root by multiplying by \r\n" );
document.write( ". Then we will have an\r\n" );
document.write( "even power of x under the square root and we'll be\r\n" );
document.write( "able to take the square root just by dividing the\r\n" );
document.write( "exponent by 2:\r\n" );
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document.write( "Edwin

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