document.write( "Question 830586: Precalculus
\n" ); document.write( "Find the period of y=3tan(2x-1)\r
\n" ); document.write( "\n" ); document.write( "I thought it would be pi, but my teacher says it's pi/2. Explanation would much appreciated.
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Algebra.Com's Answer #500823 by Fombitz(32388)\"\" \"About 
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Period of y=tan(x) is \"pi\".
\n" ); document.write( "However the 2 multiplier in \"tan%282x-1%29\", halves the period to \"pi%2F2\" just as \"tan%28x%2F2%29\" would double the period.
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\n" ); document.write( "\"+graph%28+300%2C+300%2C+-2%2C+2%2C+-20%2C+20%2C+3%2Atan%282x-1%29%29+\"
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