document.write( "Question 830743: A certain number of men can finish a piece of work in 10 days. If however there were 10 men less
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document.write( "it will take 10 days more for the work to be finished. How many men were there originally? \n" );
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Algebra.Com's Answer #500813 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A certain number of men can finish a piece of work in 10 days. \n" ); document.write( " If however there were 10 men less, it will take 10 days more for the work to be finished. \n" ); document.write( " How many men were there originally? \n" ); document.write( ": \n" ); document.write( "let m = the original number of men \n" ); document.write( "then \n" ); document.write( "10m = the number of man-days required to complete the job \n" ); document.write( ": \n" ); document.write( "\"If there were 10 men less, it will take 10 days more for the work to be finished\" \n" ); document.write( "That means that it would take 20 days \n" ); document.write( "20(m-10) = 10m \n" ); document.write( "20m - 200 = 10m \n" ); document.write( "20m - 10m = 200 \n" ); document.write( "10m = 200 \n" ); document.write( "m = 200/10 \n" ); document.write( "m = 20 men originally \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this; find the number of man-hrs to do the job. \n" ); document.write( "20*10 = 200 man-hrs (20 men working 10 days) \n" ); document.write( "or \n" ); document.write( "10*20 = 200 man-hrs (10 men working 20 days) \n" ); document.write( " |