document.write( "Question 8955: Find three consecutive even integers such that three times the first plus six times the second is equall to ten times the third. \n" ); document.write( "
Algebra.Com's Answer #5008 by bonster(299)\"\" \"About 
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#1: x
\n" ); document.write( "#2: x+2
\n" ); document.write( "#3: x+4\r
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\n" ); document.write( "\n" ); document.write( "three times the first plus six times the second is equall to ten times the third.\r
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\n" ); document.write( "\n" ); document.write( "3(x) + 6(x+2)=10(x+4)
\n" ); document.write( "3x+6x+2=10x+40
\n" ); document.write( "9x+2=10x+40 ..........................subtract 9x from both sides
\n" ); document.write( "(9x+2)-9x=(10x+40)-9x
\n" ); document.write( "2=x+40 .......................subtract 40 from both sides
\n" ); document.write( "(2)-40=(x+40)-40
\n" ); document.write( "-38=x
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\n" ); document.write( "\n" ); document.write( "#1: x =-38
\n" ); document.write( "#2: x+2=-38+2=-36
\n" ); document.write( "#3: x+4=-38+4=-34\r
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\n" ); document.write( "\n" ); document.write( "The three numbers are -38, -36, -34
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