document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=830652>Question 830652</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the an odd three digits<BR>\n" );
document.write( "number, which is add upto<BR>\n" );
document.write( "12, and the diffrnce<BR>\n" );
document.write( "between last two digits is<BR>\n" );
document.write( "equals to 1st two digits,<BR>\n" );
document.write( "what is that num ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #500783 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=500783\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Note for future posts: Please take the time to write out the question fully.  Tutors are giving you their time, and it helps when we have full information.<BR>\n" );
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document.write( "I'm going to make some assumptions, based on what you wrote.<BR>\n" );
document.write( "Let a, b, and c be the digits<BR>\n" );
document.write( "a + b + c = 12<BR>\n" );
document.write( "c - b = a + b<BR>\n" );
document.write( "c is an odd number<BR>\n" );
document.write( "Given those values, the easiest way is to plug in possibles.<BR>\n" );
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document.write( "The possible digits for c, knowing that the total is odd:<BR>\n" );
document.write( "1 (we can toss this one because c-b=a+b.  Not possible)<BR>\n" );
document.write( "3 (if c is 3, then a + b must be 9.  There's no way to make the c-b equation work)<BR>\n" );
document.write( "5 (if c is 5, then a + b must be 7.  There's no way to make the c-b equation work)<BR>\n" );
document.write( "7<BR>\n" );
document.write( "9 (we can toss this one because it would necessitate a & b being 1 & 2, which doesn't fit the c-b=a+b)<BR>\n" );
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document.write( "That leaves us 7.  If c is 7, then a+b must equal 5.  Combinations that would work are 5,0; 4,1; 3,2<BR>\n" );
document.write( "We know that c-b = a+5.  We've already established that a+b=5.  Therefore c-b=5.  If C is 7, then B *must* be 2.  If B is 2, then a *must* be 3.<BR>\n" );
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document.write( "The solution is 327. <<--<BR>\n" );
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