document.write( "Question 830596: 0 2pi: sin^2(x)-sq root of 3 sin(x)+1=cos^2(x) \n" ); document.write( "

Algebra.Com's Answer #500774 by lwsshak3(11628) $\"\"$ $\"About$

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[0,2pi]: sin^2(x)-sq root of 3 sin(x)+1=cos^2(x)
\n" ); document.write( "..
\n" ); document.write( " $\"sin%5E2%28x%29-sqrt%283%29sin%28x%29%2B1=cos%5E2%28x%29\"$
\n" ); document.write( " $\"sin%5E2%28x%29-sqrt%283%29sin%28x%29%2B1=1-sin%5E2%28x%29\"$
\n" ); document.write( " $\"2sin%5E2%28x%29-sqrt%283%29sin%28x%29=0\"$
\n" ); document.write( " $\"sin%28x%29%282sin%28x%29-sqrt%283%29%29=0\"$
\n" ); document.write( "..
\n" ); document.write( "sin(x)=0
\n" ); document.write( "x=0,π
\n" ); document.write( "or
\n" ); document.write( "2sin(x)-√3=0
\n" ); document.write( "sin(x)=√3/2
\n" ); document.write( "x=π/3,2π/3 (in quadrants I and II in which sin>0. \n" ); document.write( "

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