document.write( "Question 830646: state three consecutive terms in the arithmetic progression 40,33,26 ...which sum up to 15 \n" ); document.write( "
Algebra.Com's Answer #500754 by reviewermath(1029)![]() ![]() You can put this solution on YOUR website! Q: \n" ); document.write( "State three consecutive terms in the arithmetic progression 40,33,26 ...which sum up to 15. \n" ); document.write( "---------------------------------------------------- \n" ); document.write( "A: \n" ); document.write( "The common difference is equal to \n" ); document.write( "33 - 40 = 26 - 33 = -7 \n" ); document.write( "The three consecutive terms are x, x - 7, and x - 14. \n" ); document.write( "x + (x - 7) + (x - 14) = 15 \n" ); document.write( "3x - 21 = 15 \n" ); document.write( "x = (15 + 21)/3 = 12 \n" ); document.write( "x - 7 = 5 and \n" ); document.write( "x - 14 = -2 \n" ); document.write( "Three consecutive terms: 12, 5, -2 \n" ); document.write( " |