document.write( "Question 830623: A number is 1/4 of another number. If their difference is 57, find the two numbers. Show work. \n" ); document.write( "
Algebra.Com's Answer #500731 by JulietG(1812)\"\" \"About 
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Let x be the first number, and y the second number.
\n" ); document.write( "The problem tells you the following:
\n" ); document.write( "y - x = 57
\n" ); document.write( "y = 4x (you could also work it as 1/4y = x)
\n" ); document.write( "Substitute the value for y
\n" ); document.write( "4x - x = 57
\n" ); document.write( "Subtract
\n" ); document.write( "3x = 57
\n" ); document.write( "Divide by 3
\n" ); document.write( "x = 19
\n" ); document.write( "Since you know x and know that y is 4 times x, you can find y by multiplying x*4 (19*4=76)
\n" ); document.write( ".
\n" ); document.write( "Prove by putting the values into the original problem.
\n" ); document.write( "\"A number (19) is 1/4 of another number (76). If their difference is 57, find the two numbers.\"
\n" ); document.write( "76 - 19 does indeed equal 57.
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