document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=830609>Question 830609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i got 3 yards wide and 4 yards long and i have 20 feet of fence do i have enough fence to cover all 4 sides <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #500722 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=500722\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm assuming you're building a perimeter fence around the rectangle.  For that, you'll need 2 pieces of the length and 2 pieces of the width (P=2L+2L).<BR>\n" );
document.write( "Your length is 4 yards, which is 12 feet (1 yard = 3 feet).<BR>\n" );
document.write( "Your width is 3 yards, which is 9 feet (3*3=9)<BR>\n" );
document.write( "So, to build a perimeter fence, you'll need:<BR>\n" );
document.write( "(12*2) + (9*2)<BR>\n" );
document.write( "24 + 18 = 42<BR>\n" );
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document.write( "No, you do not have enough fencing.<BR>\n" );
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document.write( "I suspect a lot of students will get this wrong because they'll fail to convert yards to feet. </SPAN>\n" );
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