document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=830593>Question 830593</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the area and perimeter of 81ft by 39ft </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #500709 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=500709\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem gives you the following information:<BR>\n" );
document.write( "L = 81<BR>\n" );
document.write( "W = 39<BR>\n" );
document.write( "To find the area, multiply the width by the length (A=L*W)<BR>\n" );
document.write( "81 * 39 = 3159<BR>\n" );
document.write( "Remember that perimeter is a fence.  You'll need 2 pieces for the length and 2 for the width.  (P=2L+2W)<BR>\n" );
document.write( "(2*81)+(2*39)<BR>\n" );
document.write( "162 + 78 =240 </SPAN>\n" );
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