document.write( "Question 70199This question is from textbook
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Algebra.Com's Answer #50069 by Edwin McCravy(20056)\"\" \"About 
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document.write( "           writing equation in standard form?\r\n" );
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document.write( "               y+2= -3/4 (x+1)\r\n" );
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document.write( "Standard form consists of these 7 parts in this order:\r\n" );
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document.write( "1. A positive whole number (if possible)\r\n" );
document.write( "2. The letter x multiplied by the number in 1\r\n" );
document.write( "3. A plus or minus sign\r\n" );
document.write( "4. A whole number (if possible)\r\n" );
document.write( "5. The letter y multiplied by the number in 4\r\n" );
document.write( "6. An equal sign\r\n" );
document.write( "7. A whole number (if possible)\r\n" );
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document.write( "               y + 2 = -3/4(x + 1)\r\n" );
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document.write( "Multiply both sides by 4 to clear of fractions:\r\n" );
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document.write( "             4(y + 2) = 4[-3/4(x + 1]]\r\n" );
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document.write( "Distibute the 4 on the left. Cancel the 4's on the right:\r\n" );
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document.write( "                        1\r\n" );
document.write( "               4y + 8 = 4[-3/4(x + 1]]\r\n" );
document.write( "                             1\r\n" );
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document.write( "               4y + 8 = -3(x + 1)\r\n" );
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document.write( "Distribute the 3 on the right\r\n" );
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document.write( "               4y + 8 = -3x - 3\r\n" );
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document.write( "Add 3x to both sides:\r\n" );
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document.write( "          4y + 8 + 3x = -3x - 3 + 3x\r\n" );
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document.write( "          4y + 8 + 3x = -3        \r\n" );
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document.write( "Subtract 8 from both sides\r\n" );
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document.write( "      4y + 8 + 3x - 8 = -3 - 8 \r\n" );
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document.write( "              4y + 3x = -11\r\n" );
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document.write( "Reverse the terms on the left:\r\n" );
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document.write( "              3x + 4y = -11\r\n" );
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document.write( "That's it. It has all 7 parts in the \r\n" );
document.write( "order listed above.  All the numbers\r\n" );
document.write( "are whole numbers and the first one is \r\n" );
document.write( "positive.\r\n" );
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document.write( "Edwin

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