document.write( "Question 830548: The perimeter of a rectangle is 86cm. Twice the width exceeds the length by 2cm. Find the dimensions of the rectangle.
\n" ); document.write( "This is what I did so far ; w=width l=length
\n" ); document.write( "2w=L
\n" ); document.write( "2L+2w=86
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\n" ); document.write( "2w=L>>> 2(2w)+2w=86
\n" ); document.write( " 4w+2w=86
\n" ); document.write( " 6w=86
\n" ); document.write( " 6w/6w>>cancels out
\n" ); document.write( " 86/6=14.3
\n" ); document.write( " w=14.3\r
\n" ); document.write( "\n" ); document.write( "from there is where I get confused because it makes no sense to me
\n" ); document.write( "Can you please help me solve this problem?....\r
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Algebra.Com's Answer #500682 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"Twice the width exceeds the length by 2cm.\"
\n" ); document.write( "That is \"highlight_green%282w=L%2B2%29\".\r
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\n" ); document.write( "\n" ); document.write( "The perimeter value then means \"2w%2B2L=86\";
\n" ); document.write( "\"%28L%2B2%29%2B2L=86\";
\n" ); document.write( "and you can handle the rest.
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