document.write( "Question 830490: The product of two numbers is 2400. one number is 20 more than the other. What are the two numbers? i found the answer but not using algebra expressions, so can you explain how to use with this question. \n" ); document.write( "
Algebra.Com's Answer #500653 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
This is probably EASIER with algebra than without it.\r
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\n" ); document.write( "\n" ); document.write( "Two numbers, m and n.
\n" ); document.write( "mn=2400;
\n" ); document.write( "and
\n" ); document.write( "n=20+m.\r
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\n" ); document.write( "\n" ); document.write( "What could be easier or simpler than those two small equations?
\n" ); document.write( "You simply have this system of simultaneous equations:
\n" ); document.write( "----------
\n" ); document.write( "\"mn=2400\"
\n" ); document.write( "----------
\n" ); document.write( "\"n=m%2B20\"
\n" ); document.write( "---------\r
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\n" ); document.write( "\n" ); document.write( "Solve for m and n. The simplest thing to do is use the formula for n and substitute into the product equation.
\n" ); document.write( "\"mn=2400\"
\n" ); document.write( "\"m%28m%2B20%29=2400\"
\n" ); document.write( "\"m%5E2%2B20m=2400\"
\n" ); document.write( "\"m%5E2%2B20m-2400=0\" -------which is either factorable OR can be solved (for m) using the general solution to the quadratic formula. Once found, use the known m to compute n.
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