document.write( "Question 830365: Danielle and her brother mixed together some soil and some clay to make 10 yd^3 of soil with 84% clay content. They used 6 yd^3 of clay and 4 yd^3 of a soil that they purchased. What was the clay content of the soil that they purchased? \n" ); document.write( "
Algebra.Com's Answer #500560 by josgarithmetic(39617)\"\" \"About 
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The focus is on the concentration of the clay.\r
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\n" ); document.write( "\n" ); document.write( "using \"units\" for \"yard^3\",
\n" ); document.write( "the mixture is 6 units clay plus 4 units soil;
\n" ); document.write( "6+4*r=theClay units, where r is a fraction in DECIMAL form. That is the mixture according to the purchased used quantities of clay and soil.\r
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\n" ); document.write( "\n" ); document.write( "The first part of the description gives 10*0.84 units of clay, for the resulting mixture. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "UnitsOfClayKnown=UnitsOfClayMixed
\n" ); document.write( "\"highlight%2810%2A0.84=6%2B4%2Ar%29\"
\n" ); document.write( "If this makes sense, then GOOD.\r
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\n" ); document.write( "\n" ); document.write( "\"4r=10%280.84%29-6\"
\n" ); document.write( "\"r=%2810%280.84%29-6%29%2F4\"
\n" ); document.write( "\"r=%288.4-6%29%2F4\"
\n" ); document.write( "\"r=2.4%2F4=0.6\"
\n" ); document.write( "-
\n" ); document.write( "The soil purchased contained 60% clay.
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