document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=830276>Question 830276</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are two circular gardens A and B.The circumference of garden A is 1.760Km and the area of garden B is 25 times the area of garden A. find the circumference of garden B. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #500555 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=500555\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The two gardens are similar figures, so the ratio of areas is the square of the ratio of any linear measurement, such as the circumference or the radius.<BR>\n" );
document.write( "If the ratio of areas is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=25=5%5E2 ALIGN=MIDDLE  ALT=\"25=5%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, the ratio of the circumferences is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5 ALIGN=MIDDLE  ALT=\"5\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and the circumference of garden B is 5 times the circumference of garden A, or<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2A%281.760Km%29=highlight%288.800Km%29 ALIGN=MIDDLE  ALT=\"5%2A%281.760Km%29=highlight%288.800Km%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " <BR>\n" );
document.write( "ANOTHER WAY:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r ALIGN=MIDDLE  ALT=\"r\"   DISABLED_style= \"max-width:90%; height:auto;\" >= radius of the small circle (garden A)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"a=pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >= area of the small circle (garden A)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R ALIGN=MIDDLE  ALT=\"R\"   DISABLED_style= \"max-width:90%; height:auto;\" >= radius of the large circle (garden B)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=pi%2AR%5E2 ALIGN=MIDDLE  ALT=\"A=pi%2AR%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >= area of the large circle (garden B)<BR>\n" );
document.write( "The problem says that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%2Fa=25 ALIGN=MIDDLE  ALT=\"A%2Fa=25\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "So, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2AR%5E2%2F%28pi%2Ar%5E2%29=25 ALIGN=MIDDLE  ALT=\"pi%2AR%5E2%2F%28pi%2Ar%5E2%29=25\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R%5E2%2Fr%5E2=25 ALIGN=MIDDLE  ALT=\"R%5E2%2Fr%5E2=25\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28R%2Fr%29%5E2=25 ALIGN=MIDDLE  ALT=\"%28R%2Fr%29%5E2=25\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28R%2Fr%29%5E2=5%5E2 ALIGN=MIDDLE  ALT=\"%28R%2Fr%29%5E2=5%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R%2Fr=5 ALIGN=MIDDLE  ALT=\"R%2Fr=5\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R=5r ALIGN=MIDDLE  ALT=\"R=5r\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The circumference of the small circle (garden A) is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2Ar=1.760Km ALIGN=MIDDLE  ALT=\"2pi%2Ar=1.760Km\"   DISABLED_style= \"max-width:90%; height:auto;\" > .<BR>\n" );
document.write( "At this point we could solve for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r ALIGN=MIDDLE  ALT=\"r\"   DISABLED_style= \"max-width:90%; height:auto;\" > , and then calculate <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R ALIGN=MIDDLE  ALT=\"R\"   DISABLED_style= \"max-width:90%; height:auto;\" > and then the circumference of garden B.<BR>\n" );
document.write( "An easier way forward, is found think in a way a bit more abstract:<BR>\n" );
document.write( "The circumference of the large circle (garden B) is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2pi%2AR=2pi%2A%285r%29=5%282pi%2Ar%29=5%2A%281.760Km%29=highlight%288.800Km%29 ALIGN=MIDDLE  ALT=\"2pi%2AR=2pi%2A%285r%29=5%282pi%2Ar%29=5%2A%281.760Km%29=highlight%288.800Km%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );