document.write( "Question 830359: The number of bicycles in a repair shop is 7 time the number of tricycles in the shop. There are 221 wheels in the repair shop. How many bicycles are in the shop?\r
\n" ); document.write( "\n" ); document.write( "# B's = 7 * # T's
\n" ); document.write( "A tricycle has 3 wheel and a bicycle has 2 wheels \n" ); document.write( "

Algebra.Com's Answer #500550 by Edwin McCravy(20060) $\"\"$ $\"About$

You can put this solution on YOUR website!
The number of bicycles in a repair shop is 7 time the number of tricycles in the shop. There are 221 wheels in the repair shop. How many bicycles are in the shop?\r
\n" ); document.write( "\n" ); document.write( "# B's = 7 * # T's
\n" ); document.write( "

\r\n" );
document.write( "That's correct, so just write that as:\r\n" );
document.write( "\r\n" );
document.write( "B = 7T\r\n" );
document.write( "

\n" ); document.write( "A tricycle has 3 wheel and a bicycle has 2 wheels
\n" ); document.write( "

\r\n" );
document.write( "That's correct so\r\n" );
document.write( "\r\n" );
document.write( "So # T's TIMES 3 = # T-wheels \r\n" );
document.write( "\r\n" );
document.write( "write that as 3T\r\n" );
document.write( "\r\n" );
document.write( "and\r\n" );
document.write( "\r\n" );
document.write( "# B's TIMES 2 = # B-wheels\r\n" );
document.write( "\r\n" );
document.write( "Write that as 2B\r\n" );
document.write( "\r\n" );
document.write( "Then read this:\r\n" );
document.write( "\r\n" );
document.write( "There are 221 wheels in the repair shop\r\n" );
document.write( "\r\n" );
document.write( "And write\r\n" );
document.write( "\r\n" );
document.write( "2B + 3T = 221\r\n" );
document.write( "\r\n" );
document.write( "So you have these two equations:\r\n" );
document.write( "\r\n" );
document.write( "B = 7T\r\n" );
document.write( "2B + 3T = 221\r\n" );
document.write( "\r\n" );
document.write( "Since B equals 7T from the first equation, put (7T) in place of\r\n" );
document.write( "B in the second equation:\r\n" );
document.write( "\r\n" );
document.write( "2(7T) + 3T = 221\r\n" );
document.write( "\r\n" );
document.write( "Simply 2(7T) as 14T and replace 2(7T) by 14T\r\n" );
document.write( "\r\n" );
document.write( "14T + 3T = 221\r\n" );
document.write( "\r\n" );
document.write( "Add the like terms 14T plus 3T and get 17T, so put 17T\r\n" );
document.write( "in place of 14T + 3T:\r\n" );
document.write( "\r\n" );
document.write( "     17T = 221\r\n" );
document.write( "\r\n" );
document.write( "Divide both sides by 17\r\n" );
document.write( "\r\n" );
document.write( "     = \r\n" );
document.write( "\r\n" );
document.write( "Cancel the 17s on the left sides of the equal sign:\r\n" );
document.write( "Divide 221 by 17 on the right:\r\n" );
document.write( "\r\n" );
document.write( "    T = 13\r\n" );
document.write( "\r\n" );
document.write( "So there are 13 tricycles.\r\n" );
document.write( "\r\n" );
document.write( "Now go back to the equation:\r\n" );
document.write( "\r\n" );
document.write( "    B = 7T\r\n" );
document.write( "\r\n" );
document.write( "and now that we know that T = 13, we substitute (13)\r\n" );
document.write( "for T\r\n" );
document.write( "\r\n" );
document.write( "    B = 7(13)\r\n" );
document.write( "\r\n" );
document.write( "Then we multiply 7×13 and get 91\r\n" );
document.write( "\r\n" );
document.write( "So there are 91 bicycles, and 13 tricycles.\r\n" );
document.write( "\r\n" );
document.write( "------------------------\r\n" );
document.write( "Checking:\r\n" );
document.write( "The 91 bicycles have 91×2 or 182 wheels.\r\n" );
document.write( "The 13 tricycles have 13×3 or 39 wheels.\r\n" );
document.write( "---------------------------------------\r\n" );
document.write( "                     Total = 221 wheels.\r\n" );
document.write( "\r\n" );
document.write( "That checks, so we are correct.\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\n" ); document.write( "

\n" );