document.write( "Question 829988: Use factoring to solve the following quadratic equation \r
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document.write( "x(5x+2) = 2x^ 2 -6x+16 \n" );
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Algebra.Com's Answer #500330 by LinnW(1048)![]() ![]() You can put this solution on YOUR website! x(5x+2) = 2x^ 2 -6x+16 \n" ); document.write( "5x^2 + 2x = 2x^2 -6x + 16 \n" ); document.write( "add -2x^2 to each side \n" ); document.write( "3x^2 + 2x = -6x + 16 \n" ); document.write( "add 6x to each side \n" ); document.write( "3x^2 + 8x = 16 \n" ); document.write( "add -16 to each side \n" ); document.write( "3x^2 + 8x - 16 = 0 \n" ); document.write( "product of outer coefficients is -48 \n" ); document.write( "(12)(-4)= -48 \n" ); document.write( "3x^2 +12x -4x - 16 = 0 \n" ); document.write( "3x(x + 4) -4(x + 4) = 0 \n" ); document.write( "(3x - 4)(x + 4) = 0 \n" ); document.write( "3x - 4 = 0 \n" ); document.write( "3x = 4 \n" ); document.write( "x = 4/3 \n" ); document.write( "x + 4 = 0 \n" ); document.write( "x = -4 \n" ); document.write( "So solutions are 4/3 and -4 \n" ); document.write( " \n" ); document.write( " |