document.write( "Question 829988: Use factoring to solve the following quadratic equation \r
\n" ); document.write( "\n" ); document.write( "x(5x+2) = 2x^ 2 -6x+16
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Algebra.Com's Answer #500330 by LinnW(1048)\"\" \"About 
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x(5x+2) = 2x^ 2 -6x+16
\n" ); document.write( "5x^2 + 2x = 2x^2 -6x + 16
\n" ); document.write( "add -2x^2 to each side
\n" ); document.write( "3x^2 + 2x = -6x + 16
\n" ); document.write( "add 6x to each side
\n" ); document.write( "3x^2 + 8x = 16
\n" ); document.write( "add -16 to each side
\n" ); document.write( "3x^2 + 8x - 16 = 0
\n" ); document.write( "product of outer coefficients is -48
\n" ); document.write( "(12)(-4)= -48
\n" ); document.write( "3x^2 +12x -4x - 16 = 0
\n" ); document.write( "3x(x + 4) -4(x + 4) = 0
\n" ); document.write( "(3x - 4)(x + 4) = 0
\n" ); document.write( "3x - 4 = 0
\n" ); document.write( "3x = 4
\n" ); document.write( "x = 4/3
\n" ); document.write( "x + 4 = 0
\n" ); document.write( "x = -4
\n" ); document.write( "So solutions are 4/3 and -4
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