document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70153>Question 70153</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me solve the problem...instructions...solve the system by substitution.\r<BR>\n" );
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document.write( "3x - 2y = -19<BR>\n" );
document.write( "      y = 2x + 12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50027 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50027\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=2x+12 then we substitute (2x+12) for y in the other equation and solve for x<BR>\n" );
document.write( "3x-2(2x+12)=-19<BR>\n" );
document.write( "3x-4x-24=-19<BR>\n" );
document.write( "-x=-19+24<BR>\n" );
document.write( "-x=5<BR>\n" );
document.write( "x=-5 answer now substitute (-5) for x & solve for y<BR>\n" );
document.write( "y=2*-5=12<BR>\n" );
document.write( "y=-10+12<BR>\n" );
document.write( "y=2 answer<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "3*-5-2*2=-19<BR>\n" );
document.write( "-15-4=-19<BR>\n" );
document.write( "-19=-19<BR>\n" );
document.write( " </SPAN>\n" );
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