document.write( "Question 829934: for each of the two successive years bean prices rose by 10% . at the beginning of the first year 1 kg of bean cost $20 .at the end of the second year how many grams of bean could be bought for $50 \n" ); document.write( "

Algebra.Com's Answer #500257 by LinnW(1048) $\"\"$ $\"About$

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at the end of one year, the price of 1kg of beans is (1+10%)(20)
\n" ); document.write( "= 1.10*20 = 22
\n" ); document.write( "at the end of year 2, the price of 1kg of beans is (1+10%)(22)
\n" ); document.write( "= 1.10*22 = 24.2
\n" ); document.write( "So we can purchase 1KG of beans for $24.20.
\n" ); document.write( "Solving for KG/dollar 1KG/24.20 = (1/24.2)KG/dollar
\n" ); document.write( "$50(1/24.2)= 2.066116KG = 2.0661 grams
\n" ); document.write( " \n" ); document.write( "

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