document.write( "Question 829841: Use the equation y=a*(x+4)^2+2 to find the equation whose curve passes through the origin. \n" ); document.write( "
Algebra.Com's Answer #500207 by LinnW(1048)\"\" \"About 
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y=a*(x+4)^2+2
\n" ); document.write( "to pass through the origin (0,0) we need x = 0 and y = 0
\n" ); document.write( "0=a*(0+4)^2+2
\n" ); document.write( "0=a(4^2)+2
\n" ); document.write( "0=a(16)+2
\n" ); document.write( "add -2 to each side
\n" ); document.write( "-2=16a
\n" ); document.write( "divide each side by 16
\n" ); document.write( "-2/16=a
\n" ); document.write( "a = -1/8
\n" ); document.write( "substituting in y=a*(x+4)^2+2
\n" ); document.write( "0=(-1/8)(0+4)+2
\n" ); document.write( "0=(-1/8)(4)+2
\n" ); document.write( "0=-2+2
\n" ); document.write( "So the value of a that will produce an equation that passes through
\n" ); document.write( "the origin is -1/8
\n" ); document.write( "The equation we want is
\n" ); document.write( "y=(-1/8)(x+4)^2+2
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