document.write( "Question 829728: a man is 5 times as old as his daughter. the man's son is 2 years older than his sister. in 10 years the sum of their three ages is 81. what are each of their ages? \n" ); document.write( "
Algebra.Com's Answer #500134 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! a man is 5 times as old as his daughter. the man's son is 2 years older than his sister. in 10 years the sum of their three ages is 81. what are each of their ages? \n" ); document.write( "*** \n" ); document.write( "at present: \n" ); document.write( "let x=daughter's age \n" ); document.write( "5x=fathers age \n" ); document.write( "x+2=son's age \n" ); document.write( ".. \n" ); document.write( "10 yrs hence: \n" ); document.write( "x+10=daughter's age \n" ); document.write( "5x+10=fathers age \n" ); document.write( "x+12=son's age \n" ); document.write( "x+10+5x+10+x+12=81 \n" ); document.write( "7x+32=81 \n" ); document.write( "7x=49 \n" ); document.write( "x=7 \n" ); document.write( "5x=35 \n" ); document.write( "x+2=9 \n" ); document.write( "daughter's age=7 \n" ); document.write( "father's age=35 \n" ); document.write( "son's age=9 \n" ); document.write( " |