document.write( "Question 829728: a man is 5 times as old as his daughter. the man's son is 2 years older than his sister. in 10 years the sum of their three ages is 81. what are each of their ages? \n" ); document.write( "
Algebra.Com's Answer #500134 by lwsshak3(11628)\"\" \"About 
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a man is 5 times as old as his daughter. the man's son is 2 years older than his sister. in 10 years the sum of their three ages is 81. what are each of their ages?
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\n" ); document.write( "at present:
\n" ); document.write( "let x=daughter's age
\n" ); document.write( "5x=fathers age
\n" ); document.write( "x+2=son's age
\n" ); document.write( "..
\n" ); document.write( "10 yrs hence:
\n" ); document.write( "x+10=daughter's age
\n" ); document.write( "5x+10=fathers age
\n" ); document.write( "x+12=son's age
\n" ); document.write( "x+10+5x+10+x+12=81
\n" ); document.write( "7x+32=81
\n" ); document.write( "7x=49
\n" ); document.write( "x=7
\n" ); document.write( "5x=35
\n" ); document.write( "x+2=9
\n" ); document.write( "daughter's age=7
\n" ); document.write( "father's age=35
\n" ); document.write( "son's age=9
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