document.write( "Question 829796: Log(base 10)16-log(base10)(2t)=log(base 3)10 \n" ); document.write( "

Algebra.Com's Answer #500130 by lwsshak3(11628) $\"\"$ $\"About$

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Log(base 10)16-log(base10)(2t)=log(base 3)10
\n" ); document.write( " $\"log%28%2816%29%29-log%28%282t%29%29=log%283%2C%2810%29%29\"$
\n" ); document.write( " $\"log%28%2816%2F2t%29%29\"$ =2.0959
\n" ); document.write( "10^(2.0959)≈16/2t
\n" ); document.write( "124.7096≈16/2t
\n" ); document.write( "2t≈0.1283
\n" ); document.write( "t≈0.0641 \n" ); document.write( "

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