document.write( "Question 829765: Carol is 15 years older than her sister amanda.Mike is two times as old as amanda.the sum of their ages is 35. How old is carol?
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\n" ); document.write( "My atempt was: amanda;a+15=35
\n" ); document.write( " carol;a
\n" ); document.write( " mike;2a
\n" ); document.write( "then i subtracted 15 from 35 and got 20=3a because i added amanda,mike and carol's a. im stuck after here i dont know what to do.
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Algebra.Com's Answer #500080 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"a\"= Amanda's age
\n" ); document.write( "\"a%2B15\"= Carol's age (because Carol is 15 years older than Amanda)
\n" ); document.write( "\"2a\"= Mike's age (because Mike is two times as old as Amanda)
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\n" ); document.write( "The equation to solve is
\n" ); document.write( "\"a%2B%28a%2B15%29%2B%282a%29=35\"
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\n" ); document.write( "Solving:
\n" ); document.write( "\"a%2B%28a%2B15%29%2B%282a%29=35\"
\n" ); document.write( "\"a%2Ba%2B15%2B2a=35\"
\n" ); document.write( "\"a%2Ba%2B2a%2B15=35%7D%7D%0D%0A%7B%7B%7B4a%2B15=35\"
\n" ); document.write( "\"4a=35-15\"
\n" ); document.write( "\"4a=20\"
\n" ); document.write( "\"a=20%2F4\"
\n" ); document.write( "\"a=5\" , so
\n" ); document.write( "\"a%2B15=5%2B15\"
\n" ); document.write( "\"a%2B15=highlight%2820%29\"
\n" ); document.write( "Carol is \"highlight%2820%29\" years old.
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