document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70025>Question 70025</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is x\r<BR>\n" );
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document.write( "-3(x-6)=15-3x\r<BR>\n" );
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document.write( "-4(5x-2)=8(4-4x)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50007 by </B><A HREF=/tutors/aboutme.mpl?userid=music974><B>music974(43)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=music974><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50007\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -3(x-6)=15-3x the first step would be to distribute to get -3x+18=15-3x. Move the -3x to the other side to get 18=15 so there is no solution for x.  For the other problem -4(5x-2)=8(4-4x) also start by distributing to get -20x+8=32-32x. Add 20x to both sides so the equation is 8=32-12x. Then subtract 32 to both sides to get -24=-12x. Divide both sides by -12 so that x=2. </SPAN>\n" );
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