document.write( "Question 829571: 3-cosx=3sin^2x\r
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Algebra.Com's Answer #500057 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
3-cos(x) = 3sin^2(x)
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\n" ); document.write( "3 - cos(x) = 3(1-cos^2(x))
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\n" ); document.write( "3 - cos(x) = 3 - 3cos^2(x)
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\n" ); document.write( "3cos^2(x)-cos(x) = 0
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\n" ); document.write( "cos(x)[3cos(x)-1] = 0
\n" ); document.write( "cos(x) = 0 or cos(x) = 1/3
\n" ); document.write( "x = pi/2 or (3/2)pi or +-1.2310 radians
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\n" ); document.write( "\n" ); document.write( "cosx/1-sinx=1-sinx/cosx
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\n" ); document.write( "Cross-multiply to get:
\n" ); document.write( "cos^2(x) = 1-2sin(x)+sin^2(x)
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\n" ); document.write( "1-sin^2(x) = 1 - 2sin(x) + sin^2(x)
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\n" ); document.write( "2sin^2(x) -2sin(x) = 0
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\n" ); document.write( "sin(x)[2sin(x)-1] = 0
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\n" ); document.write( "sin(x) = 0 or sin(x) = 1/2
\n" ); document.write( "x = 0 or pi or pi/6 or (5/6)pi
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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