document.write( "Question 70130This question is from textbook
\n" ); document.write( ": please help me in this question: The denominator of a fraction is 1 less than twice the numerator. If 7 is added to both the numerator and denominator the resulting fraction has s value of 7/10. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #50005 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The denominator of a fraction is 1 less than twice the numerator. If 7 is added to both the numerator and denominator the resulting fraction has s value of 7/10. Find the original fraction.
\n" ); document.write( "-------------
\n" ); document.write( "Let the numerator of the original fraction be \"x\"
\n" ); document.write( "Then the denominator of the original fraction is \"2x-1\"
\n" ); document.write( "----------
\n" ); document.write( "EQUATION:
\n" ); document.write( "Add 7 to both numerator and denominator.
\n" ); document.write( "Then [x+7]/[2x-1+7] = 7/10
\n" ); document.write( "7(2x+6) = 10(x+7)
\n" ); document.write( "14x+42 = 10x+70
\n" ); document.write( "4x=28
\n" ); document.write( "x=7 (original numerator)
\n" ); document.write( "2x-1= 13 (original denominator)
\n" ); document.write( "----------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "( \n" ); document.write( "
\n" );