document.write( "Question 829624: the length of a rectangle is three more than twice the width determine the dimensions that will give a total area of 27m^2
\n" ); document.write( "please help,i'm completely stuck
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Algebra.Com's Answer #499969 by lwsshak3(11628)\"\" \"About 
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the length of a rectangle is three more than twice the width determine the dimensions that will give a total area of 27m^2
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\n" ); document.write( "let x=width of rectangle
\n" ); document.write( "2x+3=length of rectangle
\n" ); document.write( "area=length*width
\n" ); document.write( "..
\n" ); document.write( "x(2x+3)=27
\n" ); document.write( "2x^2+3x=27
\n" ); document.write( "2x^2+3x-27=0
\n" ); document.write( "(2x+9(x-3)=0
\n" ); document.write( "x=-9/2 (reject, x>0)
\n" ); document.write( "or
\n" ); document.write( "x=3
\n" ); document.write( "2x+3=9
\n" ); document.write( "width of rectangle=3m
\n" ); document.write( "length of rectangle=9m
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