document.write( "Question 829545: Hello I have a word problem on the Pythagorean theorem. It says.... the bottom of a ladder must be placed 3 feet from a wall. The ladder is 12 feet long. How far above the ground does the ladder touch the wall? I also need help like lets say a lawn is 4 meters by 5 meters... how much is it if you cross diagonally across I dont know how to solve both of these problems.. thanxs \n" ); document.write( "
Algebra.Com's Answer #499958 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The legs of a right triangle are the 2 sides
\n" ); document.write( "that are 90 degrees to each other.
\n" ); document.write( "The 3rd side is the hypotenuse.
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\n" ); document.write( "Let \"+a+\" = one of the legs
\n" ); document.write( "Let \"+b+\" = the other leg
\n" ); document.write( "Let \"+c+\" = the hypotenuse
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\n" ); document.write( "The pythagorean theorem says:
\n" ); document.write( "\"+a%5E2+%2B+b%5E2+=+c%5E2+\"
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\n" ); document.write( "For your problem, you can say \"+a+=+3+\" ft
\n" ); document.write( "The length of the ladder is the hypotenuse,
\n" ); document.write( "so \"+c+=+12+\" ft
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\n" ); document.write( "The distance from the ground to where the ladder
\n" ); document.write( "touches the wall is \"+b+\", so
\n" ); document.write( "\"+3%5E2+%2B+b%5E2+=+12%5E2+\"
\n" ); document.write( "\"+9+%2B+b%5E2+=+144+\"
\n" ); document.write( "\"+b%5E2+=+135+\"
\n" ); document.write( "\"+b+=+sqrt%28135%29+\"
\n" ); document.write( "\"+b+=+11.619+\" ft
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\n" ); document.write( "check:
\n" ); document.write( "\"+a%5E2+%2B+b%5E2+=+c%5E2+\"
\n" ); document.write( "\"+a3%5E2+%2B+11.619%5E2+=+12%5E2+\"
\n" ); document.write( "\"+9+%2B+135.001+=+144+\"
\n" ); document.write( "\"+144.001+=+144+\"
\n" ); document.write( "close enough
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\n" ); document.write( "Your other problem is
\n" ); document.write( "\"+4%5E2+%2B+5%5E2+=+c%5E2+\"
\n" ); document.write( "\"+16+%2B+25+=+c%5E2+\"
\n" ); document.write( "\"+c%5E2+=+41+\"
\n" ); document.write( "\"+c+=+sqrt%2841%29+\"
\n" ); document.write( "\"+c+=+6.403+\" meters is the
\n" ); document.write( "diagonal distance\r
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