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document.write( "y =
at the point (-4,-12)\r\n" );
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document.write( "The derivative is the slope of the tangent line.\r\n" );
document.write( "The slope of the normal is the negative reciprocal of\r\n" );
document.write( "the slope of the tangent line.\r\n" );
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document.write( "So.\r\n" );
document.write( "1. We find the derivative.\r\n" );
document.write( "2. We substitute x=-4 and simplify\r\n" );
document.write( "3. We take the negative reciprocal of the result of 2\r\n" );
document.write( "4. We use the point-slope formula with this slope and the given point.\r\n" );
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document.write( "We substitute x=-4\r\n" );
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document.write( "The slope of the tangent line is
, so the slope of the\r\n" );
document.write( "normal is
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document.write( "So we want the equation of the line through (-4,-12) with slope
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document.write( "y - y1 = m(x - x1)\r\n" );
document.write( "where (x1,y1) = (-4,-12)\r\n" );
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document.write( "Multiply through by 13\r\n" );
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document.write( "13y+156 = -3(x+4)\r\n" );
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document.write( "13y+156 = -3x-12\r\n" );
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document.write( " 3x+13y = -168\r\n" );
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document.write( "Here's the graph, it looks like a normal (perpendicular) line.\r\n" );
document.write( "So it must be correct.\r\n" );
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document.write( "Edwin
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document.write( "