document.write( "Question 829503: I am trying to find the best way to know how to do this problem.
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Algebra.Com's Answer #499925 by Edwin McCravy(20060)\"\" \"About 
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document.write( "2–3÷[(2*2-5)²*3*2+1]-2+7*2\r\n" );
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document.write( "Work inside the innermost parentheses first (2*2-5), multiplication\r\n" );
document.write( "comes before subtraction, so multiply 2*2 and get 4, so replace 2*2 \r\n" );
document.write( "by 4 and copy everything else over:\r\n" );
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document.write( "2–3÷[(4-5)²*3*2+1]-2+7*2\r\n" );
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document.write( "Work inside the innermost parentheses first (4-5), There is only\r\n" );
document.write( "the one subtraction so we subtract 4-5 getting -1 and we replace\r\n" );
document.write( "(4-5) by (-1) and copy everything else over:\r\n" );
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document.write( "2–3÷[(-1)²*3*2+1]-2+7*2\r\n" );
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document.write( "Work inside the innermost parentheses first, [(-1)²*3*2+1].\r\n" );
document.write( "Exponents come before multiplication or addition, so do (-1)²\r\n" );
document.write( "and get 1, so replace (-1)² by 1 and copy everything else over:\r\n" );
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document.write( "2–3÷[1*3*2+1]-2+7*2\r\n" );
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document.write( "Work inside the innermost parentheses first, [1*3*2+1].\r\n" );
document.write( "The first multiplication comes first, so do 1*3\r\n" );
document.write( "and get 3, so replace 1*3 by 3 and copy everything else over:\r\n" );
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document.write( "2–3÷[3*2+1]-2+7*2\r\n" );
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document.write( "Work inside the innermost parentheses first, [3*2+1].\r\n" );
document.write( "The multiplication comes before addition, so do 3*2\r\n" );
document.write( "and get 6, so replace 3*2 by 6 and copy everything else over:\r\n" );
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document.write( "2–3÷[6+1]-2+7*2\r\n" );
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document.write( "Work inside the parentheses first [6+1], There is only\r\n" );
document.write( "the one addition so we add 6+1 getting 7 and we replace\r\n" );
document.write( "[6+1] by 7 and copy everything else over:\r\n" );
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document.write( "2–3÷7-2+7*2\r\n" );
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document.write( "We do multiplications and divisions as they come left\r\n" );
document.write( "to right. The division is before the multiplication so \r\n" );
document.write( "we do 3÷7, getting \"3%2F7\".  We replace the 3÷7 by \r\n" );
document.write( "\"3%2F7\" and copy everything else over:\r\n" );
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document.write( "2–\"3%2F7\"-2+7*2\r\n" );
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document.write( "Next we do the multiplication first.  7*2 = 14 so we replace\r\n" );
document.write( "the 7*2 by 14 and copy the rest over:\r\n" );
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document.write( "2–\"3%2F7\"-2+14\r\n" );
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document.write( "We do additions and subtractions left to right, so we subtract\r\n" );
document.write( "2-\"3%2F7\" and get \"14%2F7-3%2F7\" = \"11%2F7\". So we\r\n" );
document.write( "replace 2–\"3%2F7\" by \"11%2F7\" and copy the rest over:\r\n" );
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document.write( "\"11%2F7\"-2+14\r\n" );
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document.write( "We do additions and subtractions left to right, so we subtract\r\n" );
document.write( "\"11%2F7\"-2 and get \"11%2F7-14%2F7\" = \"-3%2F7\". So we\r\n" );
document.write( "replace \"11%2F7\"-2 by \"-3%2F7\" and copy the rest over:\r\n" );
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document.write( "\"-3%2F7\"+14\r\n" );
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document.write( "We add those:  \"-3%2F7%2B98%2F7\" and get \r\n" );
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document.write( "\"95%2F7\" = \"13%264%2F7\"\r\n" );
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document.write( "Edwin

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