document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=829453>Question 829453</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 14% salt solution must be mixed with a 38% salt solution to make 40 gallons of 20% salt solution?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #499863 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=499863\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 14% salt solution must be mixed with a 38% salt solution to make 40 gallons of 20% salt solution? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "salt + salt = salt<BR>\n" );
document.write( "0.14x + 0.38(40-x) = 0.20*40<BR>\n" );
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document.write( "14x + 38(40) - 38x = 20*40<BR>\n" );
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document.write( "-24x = -18*40<BR>\n" );
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document.write( "x = (3/4)40<BR>\n" );
document.write( "x = 30 gallons (amt. of 14% solution needed)<BR>\n" );
document.write( "40-x = 10 gallons (amt. of 38% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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