document.write( "Question 828950: Suppose that the perimeter of a rectangle is 66 and the lenght is twice the width. what is the dimensions of the rectangle and what is the area \n" ); document.write( "
Algebra.Com's Answer #499832 by JulietG(1812)\"\" \"About 
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A perimeter is a fence around something. To fence a rectangle, you need 2 pieces of the length and 2 pieces of the width.
\n" ); document.write( "2L + 2W = P
\n" ); document.write( "The question gives you the following:
\n" ); document.write( "P = 66
\n" ); document.write( "L = 2W
\n" ); document.write( "Plug in the numbers:
\n" ); document.write( "2(2W) + 2W = 66
\n" ); document.write( "Multiply:
\n" ); document.write( "4W + 2W = 66
\n" ); document.write( "Add the Ws:
\n" ); document.write( "6W = 66
\n" ); document.write( "Divide by 6
\n" ); document.write( "W = 11
\n" ); document.write( ".
\n" ); document.write( "Now that you have the width, you can find the length. \"the length is twice the width\" L = 2*11, or 22.
\n" ); document.write( ".
\n" ); document.write( "Let's prove this correct.
\n" ); document.write( "2L + 2W = 66
\n" ); document.write( "2(22) + 2(11) = 66
\n" ); document.write( "44 + 22 does indeed equal 66. \n" ); document.write( "
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