document.write( "Question 829058: The length of a rectangle is three times its width.
\n" ); document.write( "If the perimeter of the rectangle is 80ft, find its area. \n" ); document.write( "

Algebra.Com's Answer #499831 by JulietG(1812) $\"\"$ $\"About$

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You want to put up a perimeter fence around the rectangle. That fencing will require two pieces the length of the land and two pieces the width of the land.
\n" ); document.write( "2L + 2W = P
\n" ); document.write( "The question gives you the total, 80.
\n" ); document.write( "It also gives you the value of the length as 3W.
\n" ); document.write( "Let's put in the information:
\n" ); document.write( "2(3W) + 2W = 80
\n" ); document.write( "Multiply:
\n" ); document.write( "6W + 2W = 80
\n" ); document.write( "Add:
\n" ); document.write( "8W = 80
\n" ); document.write( "Divide each side by 8:
\n" ); document.write( "W = 10
\n" ); document.write( ".
\n" ); document.write( "Since we know that the length is three times the W, we can multiply 3*10 to get 30.
\n" ); document.write( "The length is 30 and the width is 10.
\n" ); document.write( ".
\n" ); document.write( "Put this back into the original equation to prove it.
\n" ); document.write( "2L + 2W = 80
\n" ); document.write( "(2*30)+(2*10) = 80
\n" ); document.write( "60 + 20 does indeed equal 80. \n" ); document.write( "

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