document.write( "Question 828778: Mary is 2 times Tim's age. Tim is 5 more than Gina's age. Mary is 3 times Gina's age. How old are they altogether? \n" ); document.write( "
Algebra.Com's Answer #499830 by JulietG(1812)\"\" \"About 
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Let M = Mary's age
\n" ); document.write( "Let T = Tim's age
\n" ); document.write( "Let G = Gina's age
\n" ); document.write( ".
\n" ); document.write( "The question tells us the following:
\n" ); document.write( "M = 2T
\n" ); document.write( "T = G+5
\n" ); document.write( "M = 3G
\n" ); document.write( "or, M = 2T = 3G
\n" ); document.write( "Substitute the value for T
\n" ); document.write( "M = 2(G+5)
\n" ); document.write( "M = 2G + 10
\n" ); document.write( "Now substitute the value given for M
\n" ); document.write( "3G = 2G + 10
\n" ); document.write( "Subtract 2G from each side:
\n" ); document.write( "G = 10
\n" ); document.write( ".
\n" ); document.write( "Now that we know Gina's age, we can plug the others in.
\n" ); document.write( "Mary is 3x Gina's age, or 30
\n" ); document.write( "Tim is 5 years older than Gina, or 15 (we can prove that by the other statement that Mary is twice Tim's age)
\n" ); document.write( ".
\n" ); document.write( "Add them together:
\n" ); document.write( "Mary 30 + Tim 15 + Gina 10 = 55 \n" ); document.write( "
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