document.write( "Question 829173: The length of a rectangle is 5 cm more than twice the width. The perimeter of the rectangle is 34 cm. find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #499827 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! What is a perimeter? It's the area around. Think of a perimeter fence - that's the amount of fence you need to keep predators out of your land. The formula for perimeter is 2W + 2L (2 pieces of fence for each of the lengths and 2 pieces of fence for each of the widths). \n" ); document.write( ". \n" ); document.write( "The problem tells us that the L pieces are (2*W)+5 \n" ); document.write( "It also gives us the total, 34. Now we just need to plug in numbers. \n" ); document.write( ". \n" ); document.write( "2W + 2L = 34 \n" ); document.write( "2W + 2(2W+5)= 34 (we just substituted the value for L, given in the problem) \n" ); document.write( "2W + 4W + 10 = 34 (distributed the 2 on the outside of the brackets) \n" ); document.write( "Add the Ws: \n" ); document.write( "6W + 10 = 34 \n" ); document.write( "Subtract 10 from each side: \n" ); document.write( "6W = 24 \n" ); document.write( "Divide each side by 6: \n" ); document.write( "W = 4 \n" ); document.write( ". \n" ); document.write( "If the width is 4, we're told that the length is 5 more than twice the width, or (2*4)+5, which is 13. \n" ); document.write( ". \n" ); document.write( "Let's plug the numbers in to make certain. \n" ); document.write( "2W + 2L = 34 \n" ); document.write( "2(4) + 2(13) = 34 \n" ); document.write( "8 + 26 does indeed equal 34. \n" ); document.write( "Width = 4; length = 13 \n" ); document.write( " |