document.write( "Question 829105: If positive number is 5 less than another positive number. Six times lesser number minus 3 times the greater number is 3. Find the 2 positive numbers. \n" ); document.write( "
Algebra.Com's Answer #499824 by JulietG(1812)\"\" \"About 
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We're first told that the two numbers are:
\n" ); document.write( "x [1st number] and (x+5)[2nd number]
\n" ); document.write( "The second sentence tells us this:
\n" ); document.write( "6(x) - (3)(x+5) = 3
\n" ); document.write( "or
\n" ); document.write( "6x - (3x+15) = 3
\n" ); document.write( "which becomes
\n" ); document.write( "6x - 3x - 15 = 3
\n" ); document.write( "Add 15 to each side:
\n" ); document.write( "6x - 3x = 3 + 15
\n" ); document.write( "Add/subtract:
\n" ); document.write( "3x = 18
\n" ); document.write( "Divide each side by 3:
\n" ); document.write( "x = 6
\n" ); document.write( "Let's plug it back in to make certain:
\n" ); document.write( "\"If positive number is 5 less than another positive number. Six times lesser number minus 3 times the greater number is 3.\"
\n" ); document.write( "If x is 6, and it is 5 less than the other number, the other number is 11.
\n" ); document.write( "(6*6)-(3*11) = 3
\n" ); document.write( "36 - 33 does indeed equal 3.
\n" ); document.write( "Therefore the two numbers are 6 and 11. \n" ); document.write( "
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