document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=829384>Question 829384</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 10 less than another number. If their sum is 60, what are the numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #499816 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=499816\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let one number = x; we know from the question that the other number = x-10<BR>\n" );
document.write( "We know that added together, they are 60. <BR>\n" );
document.write( "x + (x-10) = 60<BR>\n" );
document.write( "Add the x's:<BR>\n" );
document.write( "2x -10 = 60<BR>\n" );
document.write( "Add 10 to each side:<BR>\n" );
document.write( "2x = 60 + 10 (or 70)<BR>\n" );
document.write( "Divide each side by 2<BR>\n" );
document.write( "x = 70/2 (or 35)<BR>\n" );
document.write( "Let's put it back into the original equation to see if it works.<BR>\n" );
document.write( "35 (the first number) + (35-10) (the second number) = 60<BR>\n" );
document.write( "35 + 25 does indeed equal 60. </SPAN>\n" );
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