document.write( "Question 829368: 2x+3+4+8=40
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Algebra.Com's Answer #499815 by JulietG(1812) $\"\"$ $\"About$

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\n" ); document.write( "Here's the long way:
\n" ); document.write( "2x + 3 + 4 + 8 = 40
\n" ); document.write( "Subtract 8 from each side:
\n" ); document.write( "2x + 3 + 4 = 40-8 (or 32)
\n" ); document.write( "Subtract 4 from each side:
\n" ); document.write( "2x + 3 = 32-4 (or 28)
\n" ); document.write( "Subtract 3 from each side:
\n" ); document.write( "2x = 28-3 (or 25)
\n" ); document.write( "Divide each side by 2 to get:
\n" ); document.write( "x = 25/2 (or 12 1/2)
\n" ); document.write( "Prove it by putting it back into the original equation:
\n" ); document.write( "2(12.5) + 3 + 4 + 8 = 40
\n" ); document.write( "25 + 3 + 4 + 8 does indeed = 40 \n" ); document.write( "

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